Study for the Gas Fitter Test. Enhance your knowledge with flashcards and multiple-choice questions, each accompanied by hints and explanations. Ace your exam!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

Practice this question and more.


What is the total capacitance (CT) when sizing capacitors in series with values of 12MFD and 15MFD?

  1. 5.66 CT

  2. 6.35 CT

  3. 6.97 CT

  4. 6.66 CT

The correct answer is: 6.66 CT

When capacitors are connected in series, the total capacitance (CT) can be calculated using the formula for the equivalent capacitance of capacitors in series, which is given by: 1/CT = 1/C1 + 1/C2 In this case, the values of the capacitors are 12 MFD and 15 MFD. Plugging these values into the formula, we first take the reciprocals: 1/CT = 1/12 + 1/15 To combine these fractions, you need a common denominator. The least common multiple of 12 and 15 is 60. Rewriting the fractions gives: 1/CT = 5/60 + 4/60 Now, combining the fractions: 1/CT = (5 + 4) / 60 1/CT = 9/60 To find CT, take the reciprocal of both sides: CT = 60/9 = 6.67 MFD (approximately). This value matches closely with the answer choice D, which is approximately 6.66 CT when rounded. Thus, this answer represents the correct calculation reflecting the principles of capacitance in series, demonstrating how the total capacitance decreases when capacitors