Gas Fitter Practice Test

A one-half cubic foot test dial on a meter makes one revolution every 22 seconds. Approximately how much heat is being generated?

1. 11,000 Btuh

2. 41,000 Btuh

3. 60,000 Btuh

4. 82,000 Btuh

The correct answer is: 82,000 Btuh

To determine the amount of heat being generated in this scenario, we need to first understand the relationship between the gas flow measured by the meter and the heat output. The meter in question measures gas usage in terms of volume (cubic feet), and in natural gas applications, there is a standard conversion factor to determine heat output. In this specific case, the meter is indicating a flow rate since it completes one revolution every 22 seconds. Given that one-half cubic foot of gas is measured per revolution, we can calculate the flow rate in cubic feet per hour: - There are 60 seconds in a minute and 60 minutes in an hour, so there are 3600 seconds in an hour. - Dividing the total number of seconds in an hour by the number of seconds per revolution gives us the number of revolutions in an hour: \( \frac{3600 \text{ sec}}{22 \text{ sec/rev}} \approx 163.64 \text{ rev/hr} \). - Since each revolution corresponds to half a cubic foot of gas, the total gas flow in cubic feet per hour is \( 163.64 \text{ rev/hr} \times 0.5 \text{ cubic feet/rev